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Standard XII

Physics

Voltmeter

A voltmeter o...

Question

A voltmeter of $1000 Ω$ can read potential difference of $1.5 v o l t$ . What resistance will have to be connected in series with it, in order to measure potential difference upto $6 v o l t$ with the help of this voltmeter?

3000 Ω

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500 Ω

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1, 000 Ω

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10, 000 Ω

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Solution

The correct option is A $3000 Ω$
$R_{g a l} = 1000 Ω$
$V = 1.5 V$
maximum deflection current $i_{d e f} = V / R_{g a l} = 1.5 \times 10^{- 3}$
Now we need to measure $V = 6 V$
therefore, resistance will become $R_{n e w} = V / i_{d e f} = 6 / (1.5 \times 10^{- 3}) = 4000 Ω$
Therefore, resistance required in series is $R_{s} = R_{n e w} - R_{g a l} = 4000 - 1000 = 3000 Ω$
therefore, option(A)

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A voltmeter of 1000 Ω can read potential difference of 1.5 volt. What resistance will have to be connected in series with it, in order to measure potential difference upto 6 volt with the help of this voltmeter?

The correct option is A 3000 ΩRgal=1000ΩV=1.5Vmaximum deflection current idef=V/Rgal=1.5×10−3Now we need to measureV=6Vtherefore, resistance will become Rnew=V/idef=6/(1.5×10−3)=4000ΩTherefore, resistance required in series is Rs=Rnew−Rgal=4000−1000=3000Ωtherefore, option(A)

A voltmeter of $1000 Ω$ can read potential difference of $1.5 v o l t$ . What resistance will have to be connected in series with it, in order to measure potential difference upto $6 v o l t$ with the help of this voltmeter?