Question

A voltmeter of a very high resistance is joined in the circuit as shown in figure. The voltage shown by this voltmeter will be

• A. $5V$
• B. $6V$
• C. $2.5V$
• D. $3V$

Answer 1

Answer: (B)

$6V$

The equivalent resistance of the circuit
$R_{eq}=6+\frac{8\times 8}{8+8}$
$=6+\frac{64}{16}=6+4$
$=10\Omega$
Now, current through the circuit
$i=\frac{V}{R_{eq}}=\frac{10}{10}=1A$
Now, voltmeter reading
$V^{\prime }=iR=1\times 6\Omega$
$=6V$.