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Question

A voltmeter of resistance 400 Ω is used to measure the potential difference across the 100 Ω resistor in the circuit shown in figure (32-E24). (a) What will be the reading of the voltmeter? (b) What was the potential difference across 100 Omega before the voltmeter was connected ?

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Solution

(a) Reff=100×400500+200=280

i=84280=0.3

100i=(0.3i)400

i=1.24i

5i=1.2i=0.24

Voltage measured by the voltameter =100×0.24=24V

(b) If voltameter is not connected Reff=(200+100)

=300Ω

i = 84300=0.28A

Voltage across 100Ω=(0.28×100)=28V


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