Question

A volume of ${10}^{-3}{m}^3$ is subjected to a pressure of 10 atmospheres. The change in volume is ${10}^{-6}{m}^3$. Bulk modulus of water is (Atmosphere pressure = 1x10${}^{5}N/m^2$ ) :

• A. 1x10${}^9$ N / m${}^2$
• B. 1x10${}^{10}$ N / m${}^2$
• C. 1x10${}^{12}$ N / m${}^2$
• D. 1x10${}^7$ N / m${}^2$

Answer 1

The correct option is A 1x10${}^9$ N / m${}^2$

Given,

$\Delta V=-{10}^{-6}{m}^3$

$V={10}^{-3}{m}^3$

$P=10\times {10}^{5}N/m^2$

Bulk modulus,

$B=-\frac{F/A}{\Delta V/V}$

$B=-\frac{P}{\Delta V/V}$

$B=-\frac{10\times {10}^5}{-{10}^6/{10}^{-3}}=1\times 1{-}^9$

$B=1\times {10}^{9}N/m^2$

The correct option is A.