A volume of 500 mL of a 0.1 M solution of $AgN O_{3}$ added to 500 ml of 0.1 M solution of KCl. The concentration of nitrate ion in the resulting solution is

0.05 M

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0.1 M

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0.2 M

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Reduced to zero

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Solution

The correct option is A 0.05 M

Gram equivalents of NO₃ in AgNO₃ = 0.500 × 0.1 = 0.05 gmeq
There is no gmeqs of NO₃ in KCl.
Total volume = 500ml + 500ml = 1L
Hence, concentration of NO₃ = 0.05 / 1 = 0.05M

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A volume of 500 mL of a 0.1 M solution of AgNO3 added to 500 ml of 0.1 M solution of KCl. The concentration of nitrate ion in the resulting solution is

The correct option is A 0.05 MGram equivalents of NO3 in AgNO3 = 0.500 × 0.1 = 0.05 gmeqThere is no gmeqs of NO3 in KCl.Total volume = 500ml + 500ml = 1LHence, concentration of NO3 = 0.05 / 1 = 0.05M

A volume of 500 mL of a 0.1 M solution of $AgN O_{3}$ added to 500 ml of 0.1 M solution of KCl. The concentration of nitrate ion in the resulting solution is

The correct option is A 0.05 M
Gram equivalents of NO₃ in AgNO₃ = 0.500 × 0.1 = 0.05 gmeq
There is no gmeqs of NO₃ in KCl.
Total volume = 500ml + 500ml = 1L
Hence, concentration of NO₃ = 0.05 / 1 = 0.05M