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Relative Molecular Mass

A volume of g...

Question

A volume of gaseous hydrocarbon was exploded with an excess of oxygen. The observed contraction was $2.5 V$ , and on treatment, with potash, there was a further contraction of $2 V$ . What is the molecular formula of the hydrocarbon?

A

C_{2} H_{6}

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B

C_{3} H_{6}

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C

C_{6} H_{10}

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D

C_{2} H_{4}

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Solution

The correct option is A $C_{2} H_{6}$
Initial volume of Hydrocarbon $= V m l$
$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x C O_{2} + \frac{y}{4} H_{2} O$
$x V \frac{y}{2} V$
on treatment with potash $C O_{2}$ will absorb
$x V = 2 V$
$x = 2$
Contration of volume $2.5 V$ is due to formula of $H_{2} O$ contract is due to decomponiter $C_{x} H_{y}$ for moles of $H_{2} O$ but in $H_{2} O$ then the Hydrogen
$V + \frac{V r}{4} = 2.5 V$
$4 V + V y = 10 V$
$V y = 6 | V$
$y = 6$
$∴$ Formula $= C_{2} H_{6}$ option $A$

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