A volume $V -$ temperature $T$ diagram was obtained when a given mass of gas was heated. During the heating process from state 1 to state 2, the pressure :

remains constant

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decreased

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increased

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changed erratically

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Solution

The correct option is B decreased
$y = m x + C$
$T = m V + C$ ... (i)
$P V = n R T$
$V = \frac{n R T}{P}$ ... (ii)
Substituting (ii) in (i) :
$T = m (\frac{n R T}{P}) + C$
$1 = \frac{m n R}{P} + \frac{C}{T}$
so as $T ↑ P ↓$
Pressure is decreased.

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A volume V−temperature T diagram was obtained when a given mass of gas was heated. During the heating process from state 1 to state 2, the pressure :

The correct option is B decreasedy=mx+C T=mV+C ... (i) PV=nRT V=nRTP ... (ii) Substituting (ii) in (i) : T=m(nRTP)+C 1=mnRP+CT so as T↑P↓ Pressure is decreased.

A volume $V -$ temperature $T$ diagram was obtained when a given mass of gas was heated. During the heating process from state 1 to state 2, the pressure :

The correct option is B decreased
$y = m x + C$
$T = m V + C$ ... (i)
$P V = n R T$
$V = \frac{n R T}{P}$ ... (ii)
Substituting (ii) in (i) :
$T = m (\frac{n R T}{P}) + C$
$1 = \frac{m n R}{P} + \frac{C}{T}$
so as $T ↑ P ↓$
Pressure is decreased.