A wagon weighing 1000 kg is moving with a velocity 50 km/h on smooth horizontal rails. A mass of 250 kg isdropped into it. The velocity with which it moves now is
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Solution
Given, Mass of wagon , m1 = 1000kg Velocity of wagon, V1= 50km/h After dropping 250kg mass into wagon, mass of wagon m2= 1000+250= 1250 kg
Now Velocity of wagon,V2 = ?
By principle of conservation of momentum,m1V1 = m2V2 V2= (m1V1) / m2 = (1000 * 50) / 1250 = 40 km/h