A wall 6m long, 5m high and 0.5 thick is to be constructed with brick, each having length 25cm, 12.5 cm height 7.5 cm. Find the number of brick required to constructed the wall, if it is given that cement and sand mixture occupy $\frac{1}{20}$ of volume of the wall.

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Solution

Dimension of the wall, L = 6m, B=5m, H=0.5m
L = 600cm, B = 500cm, H=50cm

Dimensions of each brick, L=25cm, b=12.5cm, h=7.5cm
Volume of the wall excluding cement 19/20 th of the volume of the wall and sand mixture
$∴$ Let number of bricks required = n
$n = \frac{\frac{19}{20} \times V o l u m e o f t h e w a l l}{V o l u m e o f e a c h b r i c k} = \frac{19 \times 600 \times 500 \times 50}{20 \times 25 \times 12.5 \times 7.5} = 6080$ .

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A wall 6m long, 5m high and 0.5 thick is to be constructed with brick, each having length 25cm, 12.5 cm height 7.5 cm. Find the number of brick required to constructed the wall, if it is given that cement and sand mixture occupy 120 of volume of the wall.

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