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Question

A wall is in the shape of a trapezium whose parallel sides are 50 m and 20 m. The non-parallel sides are 28 m and 26 m. Find the area of the wall.
[4 MARKS]

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Solution


Concept : 1 Mark
Application : 1 Mark
Calculation : 2 Marks

Draw a line CE parallel to AD and draw a perpendicular CF on AB.

It can be observed that AECD is a parallelogram.

CE = AD = 26 m

AE = DC = 50 m

BE = 50 − AB = 50m - 20 m = 30m

For ΔBEC,

s = Perimeter2= (26+28+30)2 =42cm

Area of the ΔBEC = s(sa)(sb)(sc) = 42(4226)(4228)(4230) = 336 cm2


Now, area of ΔBEC = 12×base×height= 12×BE×CF= 12×30×CF

CF= 67230 = 22.4cm


Area of AECD = CF × AE = 22.4 × 50 = 1120 cm2

Therefore, the area of wall = 1120 - 336 = 784 cm2.


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