A watch which gains uniformly is 3 minutes slow at noon on a Saturday. If the watch is 7 minutes and 12 seconds ahead on the following Saturday at 2 PM, when did the watch show the exact time?

Sunday 4 PM

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Monday 2 PM

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Monday 12 noon

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Tuesday 2 AM

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Solution

The correct option is B Monday 2 PM
The watch gains $3 + 7 \frac{1}{5}$ minutes in 7 days and 2 hours or 170 hours
612 seconds in 170 hours → 3.6 seconds each hour.
So, to gain 3 minutes or 180 seconds → It requires $\frac{180}{3.6}$ = 50 hours
So, it will show exact time on Monday 2 PM

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Similar questions

Q. A watch which gains uniformly is 3 minutes slow at noon on a Saturday. If the watch is 7 minutes and 12 seconds ahead on the following Saturday at 2 PM, when did the watch show the exact time?

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A watch which gains uniformly is 3 minutes slow at noon on a Saturday. If the watch is 7 minutes and 12 seconds ahead on the following Saturday at 2 PM, when did the watch show the exact time?

The correct option is B Monday 2 PMThe watch gains 3+715 minutes in 7 days and 2 hours or 170 hours 612 seconds in 170 hours → 3.6 seconds each hour. So, to gain 3 minutes or 180 seconds → It requires 1803.6 = 50 hours So, it will show exact time on Monday 2 PM

The correct option is B Monday 2 PM
The watch gains $3 + 7 \frac{1}{5}$ minutes in 7 days and 2 hours or 170 hours
612 seconds in 170 hours → 3.6 seconds each hour.
So, to gain 3 minutes or 180 seconds → It requires $\frac{180}{3.6}$ = 50 hours
So, it will show exact time on Monday 2 PM