A watch which gains uniformly is 3 minutes slow at noon on Monday and is 3 minutes 48 seconds fast at 2 p.m. on the following Monday.
At what time will the clock show the correct time?
A
2 p.m. On Tuesday
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B
2 p.m. On Wednesday
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C
3 p.m. On Thursday
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D
1 p.m. On Friday
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Solution
The correct option is B3 p.m. On Thursday Time from 12 p.m. on Monday to 2 p.m. on the following Monday =7 days 2 hours =170 hours. So The watch gains 3+345 min. or 34/5 minute in 170 hr. Now, if 34/5 min. are gained in 170 hrs. then 3 min. are gained in 170∗534∗3 hr =75 hr Watch is correct 3 days 3 hrs. after 12 p.m. on Monday i.e., it will be correct at 3 p.m. on Thursday. Thus Option C is correct answer.