A water bed is $2.00 m$ on a side and $30.0 c m$ deep. Find the pressure that the water bed exerts on the floor. Assume that the entire lower surface of the bed makes contact with the floor.
Density of water, $ρ = 1000 k g / m^{3}; g = 10 m / s^{2}$ .

2000 P a

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3000 P a

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3500 P a

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4000 P a

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Solution

The correct option is C $3000 P a$
Pressure on a surface is the force applied on it perpendicularly per unit area.
Hence pressure= $\frac{F o r c e}{A r e a}$
$= \frac{m g}{A} = \frac{V ρ g}{A} = \frac{0.3 \times 2 \times 2 \times 1000 \times 10}{2 \times 2} P a$
$= 3000 P a$

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