wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A water droplet splits into 27 identical small droplets. The pressure difference between the inner and outer surface of the big droplet will be

A
Same as that of smaller droplet
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1/3 rd of the pressure difference for smaller droplet.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1/4 th of the pressure difference for smaller droplet.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1/3 rd of the pressure difference for smaller droplet.
Let the radius of bigger droplet is R and radius of smaller droplets be r.
Applying volume conservation for bigger and smaller droplets,
43πR3=27×43πr3

(Rr)3=27
Rr=3
r=R3
The pressure difference between the inner and outer surface of bigger water droplet( consists of single surface) is given as,
ΔPB=2TR
similarly for smaller water droplet,
ΔPS=2Tr=2T(R3)=6TR
Hence,
ΔPB=ΔPS3
Option (b) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon