A water jet- whose cross sectional are is -a- strikes a wall making an angle - - - with the normal and rebounds elastically- The velocity of water of density -d- is v- Force exerted on wall is

The correct option is A 2av^2d cosθ v= velocity, d= density V= volume dVdt=av F=dPdt #160; #160; #160;[P=momentum] ...

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Byju's Answer

Standard XII

Physics

Second Law of Motion

A water jet, ...

Question

A water jet, whose cross sectional are is 'a' strikes a wall making an angle ' $θ$ ' with the normal and rebounds elastically. The velocity of water of density 'd' is v. Force exerted on wall is

2 a v^{2} d c o s θ

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2 a v^{2} d s i n θ

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2 a v d c o s θ

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a v d c o s θ

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Solution

The correct option is A $2 a v^{2} d c o s θ$
$v =$ velocity, $d =$ density
$V =$ volume
$\frac{d V}{d t} = a v$
$F = \frac{d P}{d t}$ [P=momentum]
$F = \frac{d (d V (2 V cos θ)]}{d t} = (2 d v cos θ) \frac{d V}{d t}$
$F = 2 d v cos θ a v [\frac{d V}{d t} = a v]$
$F = 2 a v^{2} d cos θ$

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A water jet, whose cross sectional are is 'a' strikes a wall making an angle 'θ ' with the normal and rebounds elastically. The velocity of water of density 'd' is v. Force exerted on wall is

The correct option is A 2av2d cosθv= velocity, d= densityV= volumedVdt=avF=dPdt [P=momentum]F=d(dV(2Vcosθ)]dt=(2dvcosθ)dVdtF=2 dvcosθav[dVdt=av]F=2av2dcosθ

A water jet, whose cross sectional are is 'a' strikes a wall making an angle ' $θ$ ' with the normal and rebounds elastically. The velocity of water of density 'd' is v. Force exerted on wall is

The correct option is A $2 a v^{2} d c o s θ$
$v =$ velocity, $d =$ density
$V =$ volume
$\frac{d V}{d t} = a v$
$F = \frac{d P}{d t}$ [P=momentum]
$F = \frac{d (d V (2 V cos θ)]}{d t} = (2 d v cos θ) \frac{d V}{d t}$
$F = 2 d v cos θ a v [\frac{d V}{d t} = a v]$
$F = 2 a v^{2} d cos θ$