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Standard IX

Physics

Power

A water pump ...

Question

A water pump raises 50 litre of water through a height of 25 m in 5 s. Calculate the power of the pump required.(Take g=10 N $k g^{- 1}$ and density of water=1000 kg $m^{- 3}$ .

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Solution

Volume of water = 50 L = 50 × 10^-3 m 3
Density of water = 1000 kgm-3
Mass of water = Volume of water × density of water = 50 × 10^-3 × 1000 = 50kg

Work done in raising 50kg water to a height of 25m against the force of gravity is: W = mg × h = mgh
=501025=12500J
$P o w e r equals fraction numerator w o r k space d o n e over denominator t i m e end fraction equals 12500 over 5 equals 2500 space W$

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Power

Standard IX Physics

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A water pump raises 50 litre of water through a height of 25 m in 5 s. Calculate the power of the pump required.(Take g=10 N kg−1 and density of water=1000 kg m−3.

Volume of water = 50 L = 50 × 10^-3 m 3 Density of water = 1000 kgm-3 Mass of water = Volume of water × density of water = 50 × 10^-3 × 1000 = 50kg Work done in raising 50kg water to a height of 25m against the force of gravity is: W = mg × h = mgh =50*10*25=12500J

A water pump raises 50 litre of water through a height of 25 m in 5 s. Calculate the power of the pump required.(Take g=10 N $k g^{- 1}$ and density of water=1000 kg $m^{- 3}$ .