A water pump raises $50$ litres of water through a height of $25 m$ in $5 s$ . Calculate the power which the pump supplies. (Take $g = 10 N$ $k g^{- 1}$ and density of water $= 1000 k g m^{- 3}$ )

2500 W

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12.5 K W

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2500 K W

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None of the above

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Solution

The correct option is A $2500 W$
Here we have the volume of water as 50/1000 $m^{3}$ after converting we get this.We know that $m a s s = d e n s i t y \times v o l u m e$
$M = 1000 \times 50 / 1000 = 50 k g$ .
Force is equal to $m \times g$ $=$ $50 \times 10$ $=$ $500 N$
$W o r k d o n e = F \times s = 500 \times 25 = 12500 J$
$P o w e r = w o r k / t i m e = 12500 / 5 = 2500 W a t t$ .
Hence,power generated is $2500 W$ .

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A water pump raises 50 litres of water through a height of 25 m in 5 s. Calculate the power which the pump supplies. (Take g=10N kg−1 and density of water =1000 kgm−3)

The correct option is A 2500WHere we have the volume of water as 50/1000 m3 after converting we get this.We know that mass=density×volumeM=1000×50/1000=50kg.Force is equal to m×g = 50×10 =500NWorkdone=F×s=500×25=12500JPower=work/time=12500/5=2500Watt.Hence,power generated is 2500 W.

A water pump raises $50$ litres of water through a height of $25 m$ in $5 s$ . Calculate the power which the pump supplies. (Take $g = 10 N$ $k g^{- 1}$ and density of water $= 1000 k g m^{- 3}$ )