1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A water sample or testing gave the following data From the above data , non carbonate hardness in the water sample is use atomic weights as [Na+]=38 mg/l,∣∣Ca2+∣∣=10 mg/l [HCO−3]=183 mg/l,[Mg2+]=12 mg/l [CO2−3]=30 mg/l,[Al3+]=27 mg/l [SO2−4]=45 mg/l Ca = 40, O = 16 , Mg = 24 , Na = 23 , Al = 27, C = 12, H = 1, S = 32 (in mg/l as CaCO3)

A
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
175
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
225
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 25 Total hardness =[Mg2−]Eq.weight. of CaCO3Eq.weight. of Mg2++[Ca2+]Eq.weight of CaCO3Eq.weight of Ca2+ +[Al3−]×Eq.weight of CaCO3Eq.weight of Al3+ =12×5012+10×5020+27×509 =50+25+150=225mg/l as CaCO3 Total alkalinity = [HCO−3]×Eq.weight of CaCO3Eq.weight of HCO2−3+[CO2−3]×Eq.weight of CaCO3Eq.weight of CO2−3 =183×5061+30×5030=150+50=200mg/l Now carbonate hardness = Total hardness or total alkalinity whichever is less ∴Carbonate hardness=200mg/l Non carbonate hardness = Total hardness - Carbonate hardness = 225 - 200 = 25 mg/ l

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Introduction to Atoms
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program