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Standard IX

Mathematics

Application of Inverse Proportionality

Question 94A ...

Question

Question 94

A Water tank casts a shadow 21 m long. A tree of height 9.5 m caste a shadow 8 m long at the same time. The length of the shadows are directly proportional to their heights. Find the height of the tank.

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Solution

The height of the tree = 9.5 m
The shadow of the tree = 8 m
According to the given condition in the question, the length of the shadows are in direct proportion.
$∴ \frac{8}{9.5} = \frac{21}{x} \Rightarrow x = \frac{21 \times 9.5}{8} = \frac{199.5}{8} = 24.9375 = 24.9 m$

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Application of Inverse Proportionality

Standard IX Mathematics

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Question 94 A Water tank casts a shadow 21 m long. A tree of height 9.5 m caste a shadow 8 m long at the same time. The length of the shadows are directly proportional to their heights. Find the height of the tank.

The height of the tree = 9.5 m The shadow of the tree = 8 m According to the given condition in the question, the length of the shadows are in direct proportion. ∴89.5=21x⇒x=21×9.58=199.58=24.9375=24.9 m

Question 94

A Water tank casts a shadow 21 m long. A tree of height 9.5 m caste a shadow 8 m long at the same time. The length of the shadows are directly proportional to their heights. Find the height of the tank.

The height of the tree = 9.5 m
The shadow of the tree = 8 m
According to the given condition in the question, the length of the shadows are in direct proportion.
$∴ \frac{8}{9.5} = \frac{21}{x} \Rightarrow x = \frac{21 \times 9.5}{8} = \frac{199.5}{8} = 24.9375 = 24.9 m$