A water tank has two pipes to fill it. Pipe A can fill the tank in 2 hours , only if tank is empty. Pipe B can empty the tank in 3 hours, only if tank is full. If both the pipes start at the same time when the task is empty, calculate the number of hours will it take for the tank to be filled to 60% of its capacity?
Work efficiency of pipe A in filling tank = 12 per hour
Work efficiency of pipe B in emptying tank = −13 per hour
∴ work done by A and B together = 12−13=16per hour
Hence time taken to fill the tank 100% = 6 hours
∴ time taken to fill 60% = 6×60100 = 3.6hours
Answer is option B