wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A water tank has two pipes to fill it. Pipe A can fill the tank in 2 hours , only if tank is empty. Pipe B can empty the tank in 3 hours, only if tank is full. If both the pipes start at the same time when the task is empty, calculate the number of hours will it take for the tank to be filled to 60% of its capacity?

A
2.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
60
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3.6

Work efficiency of pipe A in filling tank = 12 per hour

Work efficiency of pipe B in emptying tank = 13 per hour

work done by A and B together = 1213=16per hour

Hence time taken to fill the tank 100% = 6 hours

time taken to fill 60% = 6×60100 = 3.6hours

Answer is option B


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Time and Work
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon