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Question

A wave disturbance in a medium is described by y(x,t)=0.02 cos(50Ο€t+Ο€2)cos(10Ο€x), where x and y are in metre and t in second

Column A Column B
1. A displacement node occurs at x=0.15 m A. (i),(ii),(iii)
2. An antinode occurs at x=0.3 m B. (i),(ii),(iv)
3. The wavelength of the wave is 0.2 m C. (ii),(iii),(iv)
4. The speed of the wave is 5.0 m/s D. all

A
a
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B
c
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C
d
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D
b
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Solution

The correct option is C d
Find speed of the wave.
Formula used: v=ωk
y=0.02 cos(50πt+π2)cos(10πx)
y=0.02sin(50πt)cos(10πx)(i)
As we know,
the standard equation of the wave is,
y=2Asin(ωt)cos(kx)(ii)
From (i) and (ii),
ω=50π,k=10π
Wave speed v=ωk=50π10π=5 m/s, (iv) is correct.

Find wavelength of the wave.
Formula used:
k=2πλ
k=2πλ=10π
λ=0.2 m,(iii) is correct.

Find position of the nodes.
Formula used: cos(kx)=0
For nodes,
cos(kx)=0=cosπ2,cos3π2,
x=π2k,3π2k,=120,320,
=0.05 m,0.15 m,,(i) is correct.

Find position of the antinodes.
Formula used: cos(kx)=±1
For antinodes, cos(kx)=±1=cos0,cosπ,cos2π
x=0,πk,2πk,3πk,
=0,0.1m,0.2m,0.3m,,(ii) is correct.
Final answer: (𝑑)

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