A wave disturbance in a medium is described by y(x,t)=0.02 cos ⎧⎪⎩50πt+π2⎫⎪⎭cos(10πx), where x and y are in metres and t in seconds
A displacement node occurs at x = 0.15 m
An antinode occurs at x = 0.3 m
The wavelength of the wave is 0.2 m
The speed of the wave is 5.0 m/s
y=0.02 cos(10πx)cos⎧⎪⎩50πt+π2⎫⎪⎭
At node, amplitude = 0
⇒cos(10πx)=0⇒10πx=π2,3π2
⇒x=120=0.05 m,0.15 m.......
At antinode, amplitude is maximum
⇒cos(10πx)=±1⇒x=0,π,2π....
⇒x=0,0.1 m,0.2 m....
Now λ=2×Distance between two nodes or antinodes
=2×0.1=0.2 m and 2πvtλ=50πt
v=25λ=25×0.2=5 m/sec.