CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A wave has a frequency of 120Hz. Two points at a distance of 9 m apart have a phase difference of 180o. The velocity of the wave is :

A
2340 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2300 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2330 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2160 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2160 m/s
Phase difference between two points of wave is ϕ=180o=π,
Time period of the wave is T=1f =1120
Time taken by wave to travel distance between given two points is given by,
t=ϕ2π×T =π2π×1120=4.16666×103

V=dt =94.16666×103 .....(d= distance between two points)

V=2160m/sec

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed Of Sound_tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon