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Question

A wave is propagating along x-axis. The displacement of particles of the medium in Z-direction at t=0 is given by: z=exp[−(x+2)2] 'x' is in meters. At t=1s, the same wave disturbance is given by: z=exp[−(2−x)2]. Then, the wave propagation velocity is

A
4m/s in + x direction
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B
4m/s in - x direction
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C
2m/s in + x direction
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D
2m/s in - x direction
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Solution

The correct option is A 4m/s in + x direction

The given equation of wave: f(x)=z0=e(x+2)2 ...........at initial position.
Let the wave be travelling with a speed of "v"
Hence the speed at any time after "t" seconds is given as:
f(x±vt)=zt=e(x+2±vt)2 where

f(x+vt)= wave travelling in negative z direction with speed "v"

f(xvt)= wave travelling in positive z direction with speed "v"
Now equating this equation for time = 1 second
z1=e(2x)2.....1

Now equating this for the general equation

z1=e(x+2±v)2....2
Now equating 1 and 2
e(2x)2=e(x+2±v)2

the above two equations are equal when v=4 and "-" sign is taken that is

e(2x)2=e(x+24)2

Hence the speed of the wave is 4m/s and since the equation of the form f(x-vt) satisfies the given condition the wave is travelling in the positive "z" direction

Hence option A is correct


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