A wave is represented by the equation y=Asin(10πx+15πt+π/3), where x is in metres and t is in seconds. What is the wavelength of this wave travelling in the positive x-direction?
A
0.5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.2m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.25m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.75m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D0.2m The equation of the wave is y=Asin(10πx+15πt+π/3) This can be written in the standard form as y=Asin2π(tT−xλ+ϕ), where T is period and λ is phase difference. y=Asin2π(15πt2π+10πx2π+π6π) =Asin2π(t215+x15+16) Comparing this with standard equation λ=15 and T=215 ∴ wavelength λ=0.2m