Question

A wave of frequency 500 Hz has a wave velocity of 350 m/s. The distance between two points which point are ${60}^0$ out of phase is $116\times {10}^{-x}m$ . Find x.

Answer 1

For a wave, $v=\lambda \nu$

$⟹\lambda =\frac{v}{\nu }$

$=\frac{350}{500}=0.7m$

Distance between points ${60}^{\circ }$ out of phase=$\frac{\lambda }{2\pi }\times \Delta \varphi$

$=\frac{\lambda }{2\pi }\times \frac{\pi }{3}=0.116m$