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Question

A wave of frequency 680 Hz has a wave velocity of 340 m/s . Find the distance between two points on a wave whose phase difference is 45.

A
0.625 cm
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B
0.625 m
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C
6.25 cm
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D
6.25 m
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Solution

The correct option is C 6.25 cm
We know that ,
phase difference (Δϕ)=2πλ× path difference (Δx)

Δx=λ2π(Δϕ)

But, v=fλ using this in the above equation we get ,

Δx=v2πf(Δϕ)
From the data given in the question,
Δx=3402×π×680×π4=116=0.0625 m or 6.25 cm

Thus, option (c) is the correct answer.

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