A wave pulse passing on a string with a speed of $40 c m s^{- 1}$ in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s ?

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Solution

v = 40 cm/sec

As velocity of a wave is constant location of maximum after 5 sec.

$= 40 \times 5$

= 200 cm along negative x-axis.

$\Rightarrow$ at x = - 2m

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A wave pulse passing on a string with a speed of 40 cm s−1 in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s ?

v = 40 cm/sec As velocity of a wave is constant location of maximum after 5 sec. =40×5 = 200 cm along negative x-axis. ⇒ at x = - 2m

A wave pulse passing on a string with a speed of $40 c m s^{- 1}$ in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s ?

v = 40 cm/sec

As velocity of a wave is constant location of maximum after 5 sec.

$= 40 \times 5$

= 200 cm along negative x-axis.

$\Rightarrow$ at x = - 2m