You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Reflection from an Open End

A wave pulse ...

Question

A wave pulse passing on a string with a speed of 40 cm $s^{- 1}$ in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s?

Open in App

Solution

$v = 40 c m / sec$
As velocity of a wave is constant location of maximum after 5 sec
$= 40 \times 5 = 200 c m$ along negative x-axis.

Suggest Corrections

Similar questions

Q. A wave is travelling along positive

x -

direction with speed

4 m/s

. Further, equation of the wave pulse at

t = 0

y (x, 0) = \frac{5}{4 + (3 x + 6)^{2}}

. The equation of the same pulse after

t s

will be

Q. Transverse waves on a string have wave speed

8.00

m/s, amplitude

0.0700 m

and wavelength

0.32 m

. The waves travel in the negative x-direction and

t = 0

the

x = 0

end of the string has its maximum upward displacement. Write a wave function describing the wave.

The equation of a wave travelling on a string stretched along the X-axis is given by

$y = A e^{- (\frac{x}{a} + \frac{t}{T})^{2}}$ .

(a) Write the dimensions of a and T. (b) Find the wave speed. (c) In which direction is the wave travelling ? (d) Where is the maximum of the pulse located at t = T ? At t = 2T ?

Q. At

t = 0

, a transverse wave pulse travelling along positive

x -

direction with speed

3 m / s

in a string described by the function

y = \frac{9}{x^{2}}

given that

x \neq 0

. Transverse velocity of particle at

x = 3 m

and

t = 3 s

will be

Q. Figure (15-E1) shows a wave pulse at t = 0. The pulse moves to the right with a speed of 10 cm s⁻¹. Sketch the shape of the string at t = 1 s, 2 s and 3 s.

Join BYJU'S Learning Program

A wave pulse passing on a string with a speed of 40 cm s−1 in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s?

v=40cm/secAs velocity of a wave is constant location of maximum after 5 sec=40×5=200cm along negative x-axis.

A wave pulse passing on a string with a speed of 40 cm $s^{- 1}$ in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s?

$v = 40 c m / sec$
As velocity of a wave is constant location of maximum after 5 sec
$= 40 \times 5 = 200 c m$ along negative x-axis.