A wave with a frequency of 30 Hz travels along a string at speed of 36 m/s and reflects off a free end. The distance of the first node from the end of the string

0.2 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.3 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.4 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.3 m
$λ = \frac{36}{30} = 1.2 m$ . An anti-node is formed at a distance of $\frac{λ}{4}$ from the free end. Hence the distance = $\frac{1.2}{4} = 0.3 m$

Suggest Corrections

Similar questions

Q. A wave frequency

100 H z

travels along a string towards its fixed end. When this wave travels back after reflection, a node is formed at a distance of

10 c m

from the fixed end. The speed of the wave (incident and reflected) is

Q. A wave of frequency

100

Hz is sent along a string towards a fixed end. When this wave travels back after reflection, a node is formed at a distance of

10

cm from the fixed end of the string. The speeds of incident(and reflected) waves are?

You have 2 pipes of length 1.20 m. One pipe is open, other has one end closed. First overtone is formed in both the pipes. Find the position of 1^st displacement node from origin

Q. A pulse of a wave train travels along a stretched string and reaches the fixed end of the string. It will be reflected back with :

Q. A

12 cm

long vibrating string is fixed at one end and free at the other end. If the speed of wave on string is

48 cm/s

and string is vibrating in second overtone, find the frequency of vibration.

Join BYJU'S Learning Program

A wave with a frequency of 30 Hz travels along a string at speed of 36 m/s and reflects off a free end. The distance of the first node from the end of the string

The correct option is B 0.3 m λ=3630=1.2m. An anti-node is formed at a distance of λ4 from the free end. Hence the distance = 1.24=0.3m

The correct option is B 0.3 m
$λ = \frac{36}{30} = 1.2 m$ . An anti-node is formed at a distance of $\frac{λ}{4}$ from the free end. Hence the distance = $\frac{1.2}{4} = 0.3 m$