Question

A waveform has a baseline of $3V$, a duty cycle of $20$%, and an amplitude of $8V$. The average voltage value is

• A. $4V$
  
• B. $4.6V$
  
• C. $1.6V$
  
• D. $11V$
  

Answer 1

The correct option is A $4V$

Baseline voltage is $3V$ and amplitude is $8V$.

As we know duty cycle $DC=\frac{T_H}{T_H+T_L}$.

In this problem it is given as $0.20$, thus we get

$0.20=\frac{T_H}{T_H+T_L}$

$⟹T_L=4T_H$

Average value of voltage $V_a=\frac{T_H\times 8+T_L\times 3}{T_H+T_L}=\frac{20}{5}=4V$

$\therefore$ Answer is A.