A weak monobasic acid is half neutralised by a strong base. If the pH of the solution is $5.4$ , its $p K_{a}$ is:

6.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $5.4$
Weak monobasic acid and salt of weak acid and strong base will form a acidic buffer.
So $p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}$
If weak monobasic acid is half neutralised so $[A c i d] = [S a l t]$
$p H = p K_{a} = 5.4$

Suggest Corrections

Similar questions

K_{b}

H A

1 M

- 55.95 k J / m o l .

1.4 k J / m o l

- 57.3 k J / m o l .

A salt is formed from a weak acid and weak base. If $p K_{b}$ > $p K_{a}$ , then the pH of that salt solution is

p H

p K_{a}

Join BYJU'S Learning Program