A weight is suspended from the ceiling of a lift by a spring balance. When the lift is stationary the spring balance reads W. If the lift suddenly falls freely under gravity, the reading on the spring balance will be
A
W
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B
2 W
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C
W2
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D
\N
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Solution
The correct option is D \N Reading of spring balance R=m(g−a) If the lift falls freely then a = g∴ R=0