Question

A weight lifter lifted a load of $200kgf$ to a height of $2.5m$ in $5s$. Take $g=10N$ $k{g}^{-1}$. Calculate the power developed by him.

• A. $10W$
• B. $1W$
• C. $1000W$
• D. $100W$

Answer 1

The correct option is C $1000W$

$Work=F\times S\times \cos \theta$.

Given mass = 200 Kgf and distance is 2.5 m and angle is 180 degree and we know that cos 180 = -1.

We know that $F=m\ast g=200\ast 10=2000N-f$

Hence $W=2000\ast 2.5=5000Joule$.

$Power=work/time$

$P=5000/5=1000Watt$.