Question

A weight '$W$' can be just supported on a rough horizontal plane by a force '$F$ ' either acting along the plane or horizontally. If $\theta$ is the angle of friction, then $\frac{F}{W}$ is

• A. $\tan \theta$
• B. $\sec \theta$
• C. $\sin \theta$
• D. $\cos \theta$

Answer 1

The correct option is A $\tan \theta$

Angle of friction, is the angle which the resultant of limiting friction and normal reaction makes with the normal reaction.
$\therefore \tan \theta =\frac{F}{R}$
or $\frac{F}{W}=\tan \theta$