Question

A weight W is supported by two cables as shown. The tension in the cable making angle $\theta$ with horizontal will be the minimum when the value of $\theta$ is

• A. $0$
• B. ${30}^{\circ }$
• C. ${60}^{\circ }$
• D. None of these

Answer 1

Answer: (C)

${60}^{\circ }$

$\frac{w}{\sin (180-60-\theta )}=\frac{T_2}{\sin (90+60)}$
$\frac{w}{\sin (120-\theta )}=\frac{T_2}{\sin \left(150\right)}$
For $T_2$ to be minimum
$\sin (120-\theta )$ max.

$sin\theta ismaximumat{60}^{\circ }$ so for this $\theta ={60}^{\circ }$