Question

A weld is made using $MIG$ welding process with the following welding parameters:

$\text{Current:}200A\text{, Voltage :}25V$

$\text{Welding speed:}18cm/min$

$\text{Wire diameter:}1.2mm\text{,}$

$\text{Wire feed rate:}4m/min\text{.}$

$\text{Thermal efficiency of the processes}65\text{\%}$

The heat input per unit length of the weld in kJ/cm is

• A. 0.28
• B. 10.83
• C. 0.18
• D. 16.66

Answer 1

The correct option is B 10.83

$\text{Heat input}=\frac{(VI\times \eta )}{\text{speed}}$

$=\frac{200\times 25\times 0.65}{\left(18/60\right)}$

$=10.833kJ/cm$