A well 20 $m$ deep and 7 $m$ in diameter is full of water. Calculate the work done in pumping the whole of water up to ground level.

Open in App

Solution

Total volume of water
$= π r^{2} h$
$= π (r)^{2} \times 20$
$V = π \times 980 = \frac{22}{7} \times 7 \times 7 \times 20$
$= 22 \times 140 m^{3}$
$1 m^{3} = 1000 k g$
$w = m g h$
h = at centre of mass
$h = 10 m$
$w = (22 \times 140 \times 10^{3}) \times 10 \times 10$

Suggest Corrections

Similar questions

Q. A cubical vessel of height 1 m is full of water. Find the work done in pumping out whole water

The radius of a well is 7 m. water init is at a depth of 20m and depth of water column is 10 m.work done in pumping out water completely from the well is,(g=10m/s²)?

The height of water level in a circular well is 7 m and its diameter is 10 m. Calculate the volume of water stored in the well.

Q. A cubical vessel of height

2

m is full of water. The work done in pumping the water out of the vessel is?

Q. A one kilowatt motor pumps out water from a

10 m

deep well. Calculate the quantity of water pumped out per second.(Take

g = 10 m / s^{2}

)

Join BYJU'S Learning Program

A well 20 m deep and 7 m in diameter is full of water. Calculate the work done in pumping the whole of water up to ground level.

Total volume of water=πr2h=π(r)2×20V=π×980=227×7×7×20=22×140m31m3=1000kgw=mghh = at centre of massh=10mw=(22×140×103)×10×10

A well 20 $m$ deep and 7 $m$ in diameter is full of water. Calculate the work done in pumping the whole of water up to ground level.

Total volume of water
$= π r^{2} h$
$= π (r)^{2} \times 20$
$V = π \times 980 = \frac{22}{7} \times 7 \times 7 \times 20$
$= 22 \times 140 m^{3}$
$1 m^{3} = 1000 k g$
$w = m g h$
h = at centre of mass
$h = 10 m$
$w = (22 \times 140 \times 10^{3}) \times 10 \times 10$