A well is dug 20 m deep and it has a diameter 7 m. The earth which is so dug out is spread evenly on a rectangular plot 22 m long and 14 m broad. What is the height of platform formed?

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Solution

Volume of pit $=$ Volume of soil on land
$\Rightarrow π {(\frac{7}{2})}^{2} = 22 \times 14 \times h$
so, $h = \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 20 \times \frac{1}{22} \times \frac{1}{14}$
$h = \frac{5}{2} = 2.5 m$
Hence, the answer is $2.5 m .$

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Q. A

20

m deep well with diameter

7

m is dug and the earth from digging is evenly spread out to form a platform

22

m by

14

m. Find the height of the platform.

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A well is dug 20 m deep and it has a diameter 7 m. The earth which is so dug out is spread evenly on a rectangular plot 22 m long and 14 m broad. What is the height of platform formed?

Volume of pit = Volume of soil on land ⇒π(72)2=22×14×hso, h=227×72×72×20×122×114 h=52=2.5mHence, the answer is 2.5m.

Volume of pit $=$ Volume of soil on land
$\Rightarrow π {(\frac{7}{2})}^{2} = 22 \times 14 \times h$
so, $h = \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 20 \times \frac{1}{22} \times \frac{1}{14}$
$h = \frac{5}{2} = 2.5 m$
Hence, the answer is $2.5 m .$