A well of diameter 3m is dug 14m deep. The earth taken out of it has been evenly spread out in the form of a circular ring of width 4m to form an embankment. Find the height of the embankment.
The correct option is
D
1.125 m
The shape of the well is cylindrical
Depth (h1) = 14m
Radius of the circular end of well(r1) = 1.5m
Width of embankment = 4m
From the figure, r2 = 4 + 1.5 = 5.5m (Radius of inner circle + outer circle)
Let height of embankment dug be h2
Volume of soil dug from well = Volume of embankment
πr12h1=π(r22−r12)h2
π×(1.5)2×14=π((5.5)2−(1.5)2)h2
π×(1.5)2×14=π(5.5−1.5)(5.5+1.5)h2
π×(1.5)2×14π×4×7=h2
Solving the above equations, h2 = 1.125m