A well of diameter $7 m$ is dug and earth from digging is evenly spread out to form a platform $22 m \times 14 m \times 2.5 m$ . Find the depth of the well.

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Solution

Volume of platform $= 22 \times 14 \times 2.5 = 770 m^{2}$
Diameter of dug $= 7 m$
Volume of dus $=$ volume of platform
$π r^{2} h = 770 \frac{22}{7} \times 7 \times 7 \times h = 770 \Rightarrow h = 5$
So depth is $5 m$

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A well of diameter 7m is dug and earth from digging is evenly spread out to form a platform 22m×14m×2.5m. Find the depth of the well.

Volume of platform =22×14×2.5=770m2Diameter of dug =7mVolume of dus = volume of platformπr2h=770227×7×7×h=770⇒h=5So depth is 5m

A well of diameter $7 m$ is dug and earth from digging is evenly spread out to form a platform $22 m \times 14 m \times 2.5 m$ . Find the depth of the well.

Volume of platform $= 22 \times 14 \times 2.5 = 770 m^{2}$
Diameter of dug $= 7 m$
Volume of dus $=$ volume of platform
$π r^{2} h = 770 \frac{22}{7} \times 7 \times 7 \times h = 770 \Rightarrow h = 5$
So depth is $5 m$