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Question

(a) What happens when propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid? Write equation of the reaction involved.
(b) What change will you observe if you test soap solution with a litmus paper (red and blue)? Give reason for your observation.
(c) What is meant by denatured alcohol? What is the need to denature alcohol?

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Solution

(a) When propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid in it, esterification takes place and an ester named methyl propanoate is formed along with water.

The chemical equation for the above reaction is:
C2H5COOH + CH3OH → C2H5COOCH3 + H2O.

(b) Soap is the salt of a strong base (sodium hydroxide) and a weak acid (carboxylic acid); therefore, it's solution with water will be also basic in nature. Hence, it will turn a red litmus paper blue.

(c) Denatured alcohol is ethyl alcohol in which small amounts of poisonous substances like methanol and copper sulphate are added to make it unfit for consumption.

Ethyl alcohol is used for manufacturing various products in different industries. Therefore, government supplies ethyl alcohol to the industries without charging production tax. In order to prevent the misuse of ethyl alcohol for drinking purposes, it is denatured by adding poisonous substances such as methanol, pyridine or copper. This makes the alcohol unfit for consumption.


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