Question

(A) What is de Broglie hypothesis?
(B) Write the formula for de Broglie wavelength.
(C) Calculate de Broglie wavelength associated with an electron accelerated by a potential difference of 100 volts.
Given mass of the electron $=9.1\times {10}^{-31}kg,h=6.634\times {10}^{-34}Js,1eV=1.6\times {10}^{-19}J$

Answer 1

A) The de Broglie hypothesis states that particles of matter can behave as both waves and particles, just like light.

B) The de Broglie wavelength is given by $\lambda =\frac{h}{p}$ where h is the Planck's constant and p be the momentum of particle.

C) When an electron is accelerated from rest through a potential difference V, the de Broglie wavelength is given by $\lambda =\frac{h}{\sqrt{2meV}}$

or $\lambda =\frac{6.634\times {10}^{-34}}{\sqrt{2(9.1\times {10}^{-31})(1.6\times {10}^{-19})\left(100\right)}}=1.23\times {10}^{-10}m=0.123nm$