Question

A)What least number should be added to 1056 so that the sum is completely divisible by 23?

B)how can you add it is to get the number 1000 question mark brackets brackets? Use only addition

Answer 1

a.

1056 ÷ 23 , quotient = 45, remainder = 19

Since remainder is not zero.

So, 1056 is not exactly divisible by 23

So, we take next multiple of 23. Next multiple = 46

So, 23 * 46 = 1058

So, 1058 is exactly divisible by 23 .

1958 - 1056 = 2


b.

your question is not clear

i guess this is the solution
888+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8=1000