A Wheatstone's bridge is constructed out of four resistance 10Ω,50Ω,100Ω and 500Ω. If a 25 volt battery is connected across 500Ω resistance then current in 500Ω resistance will be
A
5mA
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B
0.5A
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C
5A
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D
0.05A
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Solution
The correct option is D0.05A Since 25 volt battery is connected across 500 Ω
So we don't have to worry about rest of the circuit we know potential across 500Ω
which is 25V
Therefore, Current through the resistor is 25/500=0.05A