Question

A wheel as the angular acceleration of 3.0 rad/$se{c}^2$ and initial angular speed of 2.00 rad/sec. In a time of 2 sec, it has rotated through an angle (in radians) of :

• A. 4
• B. 6
• C. 10
• D. 12

Answer 1

The correct option is C 10

$=\omega t+\frac{1}{2}\alpha t^2=\left(2\right)\left(2\right)+\frac{1}{2}\left(3\right)(2{)}^2$
=4 + 6 = 10 rad