You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Correlation to Linear Motion

A wheel is ma...

Question

A wheel is made to roll without slipping, towards right, by pulling a string wrapped around a coaxial spool as shown in figure. With what velocity(in m/s) the string should be pulled so that the centre of the wheeel moves with a velocity of 3 m/s?

Open in App

Solution

at point A
$v = R ω$
$ω = \frac{v}{R}$
$ω = \frac{3}{0.3}$ $ω = 10$
velocity of string = $3 - r ω = 3 - 1 = 2$

Suggest Corrections

Similar questions

The string of a step rolling wheel is pulled by applying force F will different lines of action in two situations as shown. The wheel starts rolling without slipping due to application of the force :

Q. A wheel of radius

10 c m

can rotate freely about its centre as shown in figure. A string wrapped over its rim is pulled by a force of

5 N

. It is observed that the torque produces angular acceleration of

2 r a d

s^{- 2}

in the wheel. What is the moment of inertia of the wheel?

Q. A string is wrapped around the rim of a wheel of moment of inertia

0.20 k g - m^{2}

and radius

20 c m

. The wheel is free to rotate about its axis initially the wheel is rest. The string is now pulled by a force of

20 N

. The angular velocity of the string after

5

seconds will be :

Q. A wheel (disc) of radius

10 c m

can rotate freely about its centre as shown in figure.

A

string is wrapped over its rim and is pulled by a force of

5 N

. it is found that the torque produces an angular acceleration

20 r a d / s^{2}

in the wheel. calculate the mass of the wheel.

Q. A wheel is rolling without slipping on a horizontal plane with velocity

v

and acceleration a of centre of mass as shown in figure. Acceleration at

Join BYJU'S Learning Program

A wheel is made to roll without slipping, towards right, by pulling a string wrapped around a coaxial spool as shown in figure. With what velocity(in m/s) the string should be pulled so that the centre of the wheeel moves with a velocity of 3 m/s?

at point Av=Rωω=vRω=30.3 ω=10velocity of string = 3−rω=3−1=2

at point A
$v = R ω$
$ω = \frac{v}{R}$
$ω = \frac{3}{0.3}$ $ω = 10$
velocity of string = $3 - r ω = 3 - 1 = 2$