wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A wheel is performing combined translational and rotational motion on a frictionless horizontal surface on a truck which is moving with a constant linear velocity v=10 m/s. Centre of the wheel is also moving with a constant linear velocity v=10 m/s with respect to ground. The wheel is rotating with angular velocity ω=2 rad/s. Find velocity of point A (Which is the topmost point of wheel as shown in the figure) with respect to ground. Radius of the wheel is 1 m.


A
10^i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8^i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6^i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 8^i
With respect to ground, the wheel is performing (translation + rotational) motion.
Translational velocity of wheel (Vcom)= velocity of truck.
i.e Vcom of wheel =v=10 m/s
As we know,
VA=Vcom+ω×rAO
O is the centre of wheel and A is the highest point on the wheel.
VA=10^i+2(^k)×1(^j)
VA=10^i+2(^i) [^k×^j=^i]
VA=8^i

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon