Question

A wheel is rolling on a horizontal plane. At a certain instant, it has a velocity ${}^{\prime }{v}^{\prime }$ and acceleration ${}^{\prime }{a}^{\prime }$ of CM as shown in figure. Acceleration of

• A. $A$ is vertically upwards
• B. $B$ may be vertically downwards
• C. $C$ cannot be horizontal
• D. some points on the rim may be horizontal leftwards

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $A$ is vertically upwards
B $B$ may be vertically downwards
C $C$ cannot be horizontal
D some points on the rim may be horizontal leftwards


Tangential acceleration = $r\alpha$
Linear acceleration= $a$
Centripetal acceleration = $v^2/r$


At point A having acceleration in upwards direction.
hence, option A is correct.

Option B:

In a condition when centripetal acceleration is equal to linear acceleration body try to move vertically downwards.
Hence, option B is also correct.

Option C:
at point C tengential acceleration and linear acceleration are in a same direction. Where as no components in vertically upwards direction.
Hence, option C is also correct.

Option D:

At a point betwen A and B there have some probability when vertical component of $v^2/R$ cancel $r\alpha$, hence net acceleration will be in horizontal leftwards.
So, option D is correct.