Question

A wheel is rotating at a rate of 1000rpm and its kinetic energy is ${10}^6$ J. Determine the moment of inertia of the wheel about its axis of rotation.

Answer 1

The Angular velocity of the body is given by

$?=2?\times \frac{1000}{60}$ per second

$=\frac{100}{3}$ per second

$KE=\frac{I{?}^2}{2}={10}^6$

So $I=\frac{2x{10}^6}{{?}^2}$

$I=\frac{3x3x2x{10}^6}{{10}^4{?}^2}=\frac{1800}{{?}^2}$

$=181.96J{s}^2$